[html5] r3995 - [e] (0) Editorial fixes: mis-xreffing, too many 'when's

whatwg at whatwg.org whatwg at whatwg.org
Thu Sep 24 16:17:51 PDT 2009


Author: ianh
Date: 2009-09-24 16:17:50 -0700 (Thu, 24 Sep 2009)
New Revision: 3995

Modified:
   index
   source
Log:
[e] (0) Editorial fixes: mis-xreffing, too many 'when's

Modified: index
===================================================================
--- index	2009-09-24 23:14:34 UTC (rev 3994)
+++ index	2009-09-24 23:17:50 UTC (rev 3995)
@@ -24239,9 +24239,10 @@
   or its vertical dimension is zero) then the method must return the
   string "<code title="">data:,</code>". (This is the shortest <code title="">data:</code> URL; it represents the empty string in a <code title="">text/plain</code> resource.)</p>
 
-  <p>When the <code title=dom-canvas-toDataURL><a href=#dom-canvas-todataurl>toDataURL(<var title="">type</var>)</a></code> method, when called with one <em>or
-  more</em> arguments, must return a <code title="">data:</code> URL
-  containing a representation of the image in the format given by <var title="">type</var>. The possible values are <a href=#mime-type title="MIME
+  <p>When the <code title=dom-canvas-toDataURL><a href=#dom-canvas-todataurl>toDataURL(<var title="">type</var>)</a></code> method is called with one <em>or
+  more</em> arguments, it must return a <code title="">data:</code>
+  URL containing a representation of the image in the format given by
+  <var title="">type</var>. The possible values are <a href=#mime-type title="MIME
   type">MIME types</a> with no parameters, for example
   <code>image/png</code>, <code>image/jpeg</code>, or even maybe
   <code>image/svg+xml</code> if the implementation actually keeps
@@ -25032,11 +25033,11 @@
 
    <li>
 
-    <p>Let <span>x(<var title="">ω</var>) = (<var title="">x<sub>1</sub></var>-<var title="">x<sub>0</sub></var>)<var title="">ω</var> + <var title="">x<sub>0</sub></var></span></p>
+    <p>Let <span title="">x(<var title="">ω</var>) = (<var title="">x<sub>1</sub></var>-<var title="">x<sub>0</sub></var>)<var title="">ω</var> + <var title="">x<sub>0</sub></var></span></p>
 
-    <p>Let <span>y(<var title="">ω</var>) = (<var title="">y<sub>1</sub></var>-<var title="">y<sub>0</sub></var>)<var title="">ω</var> + <var title="">y<sub>0</sub></var></span></p>
+    <p>Let <span title="">y(<var title="">ω</var>) = (<var title="">y<sub>1</sub></var>-<var title="">y<sub>0</sub></var>)<var title="">ω</var> + <var title="">y<sub>0</sub></var></span></p>
 
-    <p>Let <span>r(<var title="">ω</var>) = (<var title="">r<sub>1</sub></var>-<var title="">r<sub>0</sub></var>)<var title="">ω</var> + <var title="">r<sub>0</sub></var></span></p>
+    <p>Let <span title="">r(<var title="">ω</var>) = (<var title="">r<sub>1</sub></var>-<var title="">r<sub>0</sub></var>)<var title="">ω</var> + <var title="">r<sub>0</sub></var></span></p>
 
     <p>Let the color at <var title="">ω</var> be the color at
     that position on the gradient (with the colors coming from the <a href=#interpolation>interpolation and extrapolation</a>
@@ -25044,11 +25045,10 @@
 
    </li>
 
-   <li><p>For all values of <var title="">ω</var> where
-   <span>r(<var title="">ω</var>) > 0</span>,
+   <li><p>For all values of <var title="">ω</var> where <span title="">r(<var title="">ω</var>) > 0</span>,
    starting with the value of <var title="">ω</var> nearest to
    positive infinity and ending with the value of <var title="">ω</var> nearest to negative infinity, draw the
-   circumference of the circle with radius <span>r(<var title="">ω</var>)</span> at position (<span>x(<var title="">ω</var>)</span>, <span>y(<var title="">ω</var>)</span>), with the color at <var title="">ω</var>, but only painting on the parts of the
+   circumference of the circle with radius <span title="">r(<var title="">ω</var>)</span> at position (<span title="">x(<var title="">ω</var>)</span>, <span title="">y(<var title="">ω</var>)</span>), with the color at <var title="">ω</var>, but only painting on the parts of the
    canvas that have not yet been painted on by earlier circles in this
    step for this rendering of the gradient.</li>
 

Modified: source
===================================================================
--- source	2009-09-24 23:14:34 UTC (rev 3994)
+++ source	2009-09-24 23:17:50 UTC (rev 3995)
@@ -26345,10 +26345,10 @@
   title="">text/plain</code> resource.)</p>
 
   <p>When the <code title="dom-canvas-toDataURL">toDataURL(<var
-  title="">type</var>)</code> method, when called with one <em>or
-  more</em> arguments, must return a <code title="">data:</code> URL
-  containing a representation of the image in the format given by <var
-  title="">type</var>. The possible values are <span title="MIME
+  title="">type</var>)</code> method is called with one <em>or
+  more</em> arguments, it must return a <code title="">data:</code>
+  URL containing a representation of the image in the format given by
+  <var title="">type</var>. The possible values are <span title="MIME
   type">MIME types</span> with no parameters, for example
   <code>image/png</code>, <code>image/jpeg</code>, or even maybe
   <code>image/svg+xml</code> if the implementation actually keeps
@@ -27271,19 +27271,22 @@
 
    <li>
 
-    <p>Let <span>x(<var title="">ω</var>) = (<var
+    <p>Let <span title="">x(<var
+    title="">ω</var>) = (<var
     title="">x<sub>1</sub></var>-<var
     title="">x<sub>0</sub></var>)<var
     title="">ω</var> + <var
     title="">x<sub>0</sub></var></span></p>
 
-    <p>Let <span>y(<var title="">ω</var>) = (<var
+    <p>Let <span title="">y(<var
+    title="">ω</var>) = (<var
     title="">y<sub>1</sub></var>-<var
     title="">y<sub>0</sub></var>)<var
     title="">ω</var> + <var
     title="">y<sub>0</sub></var></span></p>
 
-    <p>Let <span>r(<var title="">ω</var>) = (<var
+    <p>Let <span title="">r(<var
+    title="">ω</var>) = (<var
     title="">r<sub>1</sub></var>-<var
     title="">r<sub>0</sub></var>)<var
     title="">ω</var> + <var
@@ -27296,14 +27299,14 @@
 
    </li>
 
-   <li><p>For all values of <var title="">ω</var> where
-   <span>r(<var title="">ω</var>) > 0</span>,
+   <li><p>For all values of <var title="">ω</var> where <span
+   title="">r(<var title="">ω</var>) > 0</span>,
    starting with the value of <var title="">ω</var> nearest to
    positive infinity and ending with the value of <var
    title="">ω</var> nearest to negative infinity, draw the
-   circumference of the circle with radius <span>r(<var
-   title="">ω</var>)</span> at position (<span>x(<var
-   title="">ω</var>)</span>, <span>y(<var
+   circumference of the circle with radius <span title="">r(<var
+   title="">ω</var>)</span> at position (<span title="">x(<var
+   title="">ω</var>)</span>, <span title="">y(<var
    title="">ω</var>)</span>), with the color at <var
    title="">ω</var>, but only painting on the parts of the
    canvas that have not yet been painted on by earlier circles in this




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