[html5] r4326 - [e] (0) Mention what the algorithm can return. Fixing http://www.w3.org/Bugs/Pub [...]
whatwg at whatwg.org
whatwg at whatwg.org
Sun Oct 25 00:02:51 PDT 2009
Author: ianh
Date: 2009-10-25 00:02:46 -0700 (Sun, 25 Oct 2009)
New Revision: 4326
Modified:
complete.html
index
source
Log:
[e] (0) Mention what the algorithm can return.
Fixing http://www.w3.org/Bugs/Public/show_bug.cgi?id=8041
Modified: complete.html
===================================================================
--- complete.html 2009-10-25 06:38:44 UTC (rev 4325)
+++ complete.html 2009-10-25 07:02:46 UTC (rev 4326)
@@ -3070,7 +3070,9 @@
</table><div class=impl>
<p>The <dfn id=steps-for-finding-one-or-two-numbers-of-a-ratio-in-a-string>steps for finding one or two numbers of a ratio in a
- string</dfn> are as follows:</p>
+ string</dfn> are as given in the following algorithm. This algorithm
+ will return either a number, or a number and a denominator
+ character, or two numbers, or nothing.</p>
<ol><li><p>Let <var title="">input</var> be the string being
parsed.</li>
Modified: index
===================================================================
--- index 2009-10-25 06:38:44 UTC (rev 4325)
+++ index 2009-10-25 07:02:46 UTC (rev 4326)
@@ -2880,7 +2880,9 @@
</table><div class=impl>
<p>The <dfn id=steps-for-finding-one-or-two-numbers-of-a-ratio-in-a-string>steps for finding one or two numbers of a ratio in a
- string</dfn> are as follows:</p>
+ string</dfn> are as given in the following algorithm. This algorithm
+ will return either a number, or a number and a denominator
+ character, or two numbers, or nothing.</p>
<ol><li><p>Let <var title="">input</var> be the string being
parsed.</li>
Modified: source
===================================================================
--- source 2009-10-25 06:38:44 UTC (rev 4325)
+++ source 2009-10-25 07:02:46 UTC (rev 4326)
@@ -2047,7 +2047,9 @@
<div class="impl">
<p>The <dfn>steps for finding one or two numbers of a ratio in a
- string</dfn> are as follows:</p>
+ string</dfn> are as given in the following algorithm. This algorithm
+ will return either a number, or a number and a denominator
+ character, or two numbers, or nothing.</p>
<ol>
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