[whatwg] [html5] r6757 - [e] (0) Since I'm going to be editing this algorithm some more, let's bite the b [...]

[Silvia Pfeiffer]

Question on recent commit:

On Wed, Oct 26, 2011 at 9:59 AM,  <whatwg at whatwg.org> wrote:
> Author: ianh
> Date: 2011-10-25 15:59:20 -0700 (Tue, 25 Oct 2011)
> New Revision: 6757
>
> Modified:
>   complete.html
>   index
>   source
> Log:
> [e] (0) Since I'm going to be editing this algorithm some more, let's bite the bullet and do what foolip and anne wanted, which is to normalise newlines early for sanity.
>
> Modified: complete.html
> ===================================================================
> --- complete.html       2011-10-25 22:44:32 UTC (rev 6756)
> +++ complete.html       2011-10-25 22:59:20 UTC (rev 6757)
> @@ -33068,11 +33068,26 @@
>
>   <p>The <dfn id=webvtt-parser-algorithm>WebVTT parser algorithm</dfn> is as follows:</p>
>
> -  <ol><li><p>Let <var title="">input</var> be the string being parsed,
> -   after conversion to Unicode.</li>
> +  <ol><li>
>
> -   <li><p>Replace all U+0000 NULL characters in <var title="">input</var> by U+FFFD REPLACEMENT CHARACTERs.</li>
> +    <p>Let <var title="">input</var> be the string being parsed, after
> +    conversion to Unicode, and with the following transformations
> +    applied:</p>
>
> +    <ul><li><p>Replace all U+0000 NULL characters by U+FFFD REPLACEMENT
> +     CHARACTERs.</li>
> +
> +     <li><p>Replace each U+000D CARRIAGE RETURN U+000A LINE FEED
> +     (CRLF) character pair by a single U+000A LINE FEED (CRLF)
> +     character.</li>

Should this just be (LF)?

> +     <li><p>Replace all remaining U+000D CARRIAGE RETURN characters by
> +     U+000A LINE FEED (CRLF) characters.</li>

Same: should this just be (LF)?

Cheers,
Silvia.