[html5] r2054 - [] (0) Look for a '%' character after spaces after the second number when lookin [...]

[whatwg at whatwg.org]

Author: ianh
Date: 2008-08-11 18:07:10 -0700 (Mon, 11 Aug 2008)
New Revision: 2054

Modified:
   index
   source
Log:
[] (0) Look for a '%' character after spaces after the second number when looking for an error, for consistency with the earlier check. (Subject: Skipping Zs in finding a ratio) (credit: hs)

Modified: index
===================================================================
--- index	2008-08-12 00:53:42 UTC (rev 2053)
+++ index	2008-08-12 01:07:10 UTC (rev 2054)
@@ -3464,6 +3464,11 @@
    <li>Set <var title="">number2</var> to the number returned by the
     sub-algorithm in step 9.
 
+   <li>Starting with the character immediately after the last one examined by
+    the sub-algorithm in step 9, skip any characters in the string that are
+    in the Unicode character class Zs (this might match zero characters). <a
+    href="#refsUNICODE">[UNICODE]</a>
+
    <li>If there are still further characters in the string, and the next
     character in the string is a <a href="#valid2">valid denominator
     punctuation character</a>, return nothing and abort these steps.

Modified: source
===================================================================
--- source	2008-08-12 00:53:42 UTC (rev 2053)
+++ source	2008-08-12 01:07:10 UTC (rev 2054)
@@ -1443,9 +1443,9 @@
    given a value in the step 6, return nothing and abort these
    steps.</li>
 
-   <li>Otherwise, if <var title="">denominator</var> was given a value in step
-   6, return <var title="">number1</var> and <var title="">denominator</var> and abort
-   these steps.</li>
+   <li>Otherwise, if <var title="">denominator</var> was given a value
+   in step 6, return <var title="">number1</var> and <var
+   title="">denominator</var> and abort these steps.</li>
 
    <li><span>Find a number</span> in the string again, starting
    immediately after the last character that was examined by the
@@ -1457,6 +1457,11 @@
    <li>Set <var title="">number2</var> to the number returned by the
    sub-algorithm in step 9.</li>
 
+   <li>Starting with the character immediately after the last one
+   examined by the sub-algorithm in step 9, skip any characters in the
+   string that are in the Unicode character class Zs (this might match
+   zero characters). <a href="#refsUNICODE">[UNICODE]</a></li>
+
    <li>If there are still further characters in the string, and the
    next character in the string is a <span>valid denominator
    punctuation character</span>, return nothing and abort these